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Write the equation of the tangent to t...

Write the equation of the tangent to the curve `y=x^2-x+2` at the point where it crosses the y-axis.

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`y=x^2−x+2` curve which crosses y-axis that means x=0
Now, `y=x^2−x+2 `
`(dy/dx)​=2x−1`
`[(dy/dx)​]_(x=0)​=−1`
...
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