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Write the slope of the normal to the ...

Write the slope of the normal to the curve `y=1/x` at the point `(3,1/3)`

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Given, `y=1/x`
`dy/dx​=-1/x^2`
Slope of normal at a point `(3,1/3​)`
=`m=-1/(dy/dx)_(3,1/3)`
​ =`-1/(-1/3^2)`
=9
The slope of the normal to the curve is 9
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