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Find the equation of the tangent to the curve `y=x-sinxcosx` at `x=pi/2`

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Givn,`y=x-sinxcosx`
=`x-(sin(2x))/2​`
`y′=1+cos(2x)`
Substituting x=π/2
`y′(π/2)=1-cos(π)=-2`
Therefore, slope of tangent is 0.
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