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The point on the curve y^2=x where tange...

The point on the curve `y^2=x` where tangent makes `45o` angle with x-axis is `(1//2,\ 1//4)` (b) `(1//4,\ 1//2)` (c) `(4,\ 2)` (d) `(1,\ 1)`

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Given,`y^2=x`
Differentiatie both sides w.r.t. x
`2y(dy/dx)​=1`
`dy/dx​=1/(2y)`
​ Also, tangent makes an angle of `π/4`​ with x axis `dy/dx​=tan(π​/4)` =1
∴`1/(2y)=1 ...
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