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The point on the curve y=12 x-x^2 where ...

The point on the curve `y=12 x-x^2` where the slope of the tangent is zero will be `(0,\ 0)` (b) `(2,\ 16)` (c) `(3,\ 9)` (d) `(6,\ 36)`

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Let the point be P(x,y)
`y=12x−x^2`
`dy/dx​=12−2x`
`(dy/dyx)_(x_1​,y_1​)​=12−2x_1`
​ since slope of tangent is zero
so `(dy/dx​)_(x_1​,y_1)​​=0`
...
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