The slope of the tangent to the curve `x=t^2+3t-8,\ \ y=2t^2-2t-5` at point `(2,\ -1)` is `22//7` (b) `6//7` (c) `-6` (d) `7//6`

Explanation

Given curves are `x=t^2+3t−8 ... (i)`

and `y=2t^2−2t−5 ... (ii)`

At (2,−1), From (i)
`t=2 or t=−5`

From (ii)

⟹`t=2 or t=−1`

From both the solutions, we get t=2


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