The angle of intersection of the curves `y=2\ s in^2x` and `y=cos2\ x` at `x=pi/6` is `pi//4` (b) `pi//2` (c) `pi//3` (d) `pi//6`

Explanation

We have,
`y=sin^2x...(1)`

`y=cos 2x`...(2)

And
On differentiating equation (1) w.r.t x, we get


`dy/dx=4 sin x cos x`

`[dydx]_(x−π6)=4(1/2)(√3/2)=√3=m_1`(say)

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