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If bond energy of H(2),F(2) and HF are i...

If bond energy of `H_(2),F_(2)` and `HF` are in the ratio `2:1:3` and `DeltaH_(a)(H_(2))=400kJ//mol`. Then `DeltaH_(f)(HF)` is `:`

A

`0 kJ //mol`

B

`-600kJ //mol`

C

`-1200kJ//mol`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
4
`DeltaH_(f)(HF)=(1)/(2)DeltaH_(a)(H_(2))+(1)/(2)DeltaH_(a)(F_(2))-DeltaH(HF)-(1)/(2)xx400+(1)/(2)xx200-600=-300kJ//mol.`
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