The equilibrium constant for
`A(g)+B_(2)(g) hArr AB_(2)(g)" "k_(p)=100` at `522K`.
Structure of `AB_(2)` is like `H_(2)O` . If bond energy of `A-B` bond is `200 kJ//mol` and that of `B-B` bond is `100 kJ//mol,` the find `Delta S^(@)` of the above reaction `:`

Options

A. `-0.53J //mol-K`
B. `-536 J //mol-K`
C. `-550J//mol-K`
D. `-5.36J//mol-K`

Answer

2

Explanation

`DeltaH^(@)=E_(B-B)-2E_(A-B)=100-2xx200=-300kJ//mol e`
`DeltaG^(@)=-2.303xx8.314xx522log100-2.303xx8.314xx522xx2J//mol`
`=-19.99kJ//mol=DeltaH^(@)-TDeltaS^(@)`
`=-19.99xx10^(3)=-300xx10^(3)-522xxDeltaS^(@)`
`DeltaS^(@)-((-300xx19.99)xx10^(3))/(522)=-536.39J//mol e-K`.