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At 0^(@)C,DeltaH(fus)^(@)=6kJ //mol, cha...

At `0^(@)C,DeltaH_(fus)^(@)=6kJ //mol`, change of entropy for freezing of one mole of ice will be `:`

A

`oo`

B

0

C

`21.98J//mol-K`

D

`13.6J//mol-K`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaS=(DeltaH_(f)^(@))/(T_(f))=(6000)/(273)=21.97J//moll-K`
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