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For a closed container containing 100 mo...

For a closed container containing `100` mol of an ideal gas fitted with movable, frictionless, weightless piston operating such that pressure of gas remain constant at `8.21` atm, which graph repsents correct variation of log `V v//s` log `T` where `V` is in litre and `T` is in Kelvin ? `(R = 0.0821 (atmL)/(molK))`

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The correct Answer is:
1
`V=(nRT)/(P)=(100xx0.0821xxT)/(8.21)=T`
`:." "logV=logT`
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