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The conductivity of "0.1N NaOH" solutio...

The conductivity of `"0.1N NaOH"` solution is `0.022 S cm^(-1)`. To this solution equal volume of `" 0.1 N HCl` solution is added which results into decrease of conductivity of solution to `0.0055 S cm^(-1)`. The equivalent conductivity of `NaCl` solution in `S cm^(2)" equiv"^(-1)` is `:`

A

`0.011`

B

`110`

C

`0.0055`

D

`55.0`

Text Solution

Verified by Experts

The correct Answer is:
2
Normality of resulting solution `=(0.1V)/(2V)=0.05N`
`wedge_(eq)=(Kxx1000)/(N)=(0.0055xx1000)/(0.05)=110`
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