Given that `E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V` if `Fe^(2+),Fe^(3+)` and `Fe` solid are kept together then

Options

A. `Fe^(3+)` Increase
B. `Fe^(3+)` decrease
C. `Fe^(2+)//Fe^(3+)` remains unchanged
D. `Fe^(2+)` decreases

Answer

B

Explanation

`{:("Anode",,Ferarr Fe^(@+)+2e^(-),,),("Cathode",,[Fe^(3+)+e^(-)rarrFe^(2+)]xx2,,),("Cell",,Fe+2Fe^(3+)rarr3Fe^(2+),,),(E^(2)=0.77-(-0.44)=1.21V,,,,):}`
`DeltaG^(@)=( - )ve" "` Reaction is spontaneous.