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Number of electrons lost during electrol...

Number of electrons lost during electrolysis of `0.14g` of `N^(-3)` is `-(N_(0)=1` Avagadro number )

A

`0.03`

B

`0.03N_(0)`

C

`0.015N_(0)`

D

`(0.01)/(2N_(0))`

Text Solution

Verified by Experts

The correct Answer is:
2
mole `=(014)/(14)=0.01`
Mole `e^(-)` lost `=0.03`
Number of electron lost `-0.03N_(0)`
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