In the electrolysis of an aqueous potassium sulphate solution, the `Ph` of the solution in the space near an electrode increased. Which pole of the current source is the electrode connected to ?

Options

A. The positive pole
B. Could be either polde
C. The negative pole
D. Cannot be determined

Answer

C

Explanation

`K_(2)SO_(4)hArr2K^(+)+SO_(4)^(3+)`
`H_(2)OhArr H^(+)+OH^(-)`
`(pHdarr)`Anode`2OH^(-)rarrH_(2)O+(1)/(2)O_(2)+2e^(-)`
`(pHuarr)`Cathode`2H^(+)+2e^(-)rarrH_(2)O`