Calcium crystallises in a face `-` centred cubic unit cell with `a=556nm`. Calculate the density if it contained `0.1%` Vaccancy defects.

Options

A. `1.90 g//cm^(3)`
B. `1.54g//cm^(3)`
C. `3.4g//cm^(3)`
D. `5.4g//cm^(3)`

Answer

2

Explanation

Thus, density can be determined using `d=(zM)/(a^(3)N_(0))`
`d(` with Vaccance defect) `=(3.996xx40)/((0.556xx10^(-7))^(3)xx6.02xx10^(23))=1.5448g//cm^(3)`