An ideal gas undergoes a cyclic process, in which one process is isochoric, one process is isothermal and one process is adiabatic. During the isothermal process, 40 J heat is released by the gas, and during the isochoric process, 80 J heat is absorbed by the gas. if work done by the gas during adiabatic process is `W_(1)` and during isothermal process is `W_(2)` then the magnitude of `(W_(1))/(W_(2))` will be equal to:

Answer

B

Explanation

For isothermal process
`W_(2)=Q_(BC)=-40J`
for complete cycle
`Q_("cycle")=W_("cycle")`
`-40+80+0=-40+0+W`
`W_(1)=80J`