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The function 'g' defined by g(x)= sin(si...

The function 'g' defined by `g(x)= sin(sin^(-1)sqrt({x}))+cos(sin^(-1)sqrt({x}))-1` (where {x} denotes the functional part function) is (1) an even function (2) a periodic function (3) an odd function (4) neither even nor odd

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Verified by Experts

The correct Answer is:
A
`g(x)=sqrt({X})+sqrt(1-{X})-1`
if `x in I` then `g(x)=0`
if `x in I` then `{-x}=1-{x}`
`becauseg(-x)=g{x}`
`g(x)={{:(0,x in I),(g(-x), x in I):}`
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