As shown in figure process AB is isobaric, BC is adiabasic CD is isochoric and DA is isothermal, through which n-moles of monoatomic gas undergo a cyclic process. The max & min temperature in the cycle are `4T_(0)` and `T_(0)` respectively.

Options

A. `T_(B)` is greater than `T_(D)`
B. Heat is released by gas in the process CD
C. Heat is supplied to the gas in the process AB
D. `T_(C)` is greater than `T_(A)`

Answer

A, B, C, D

Explanation

DA is isothermal
`becauseT_(D)=T_(A)`
`TalphaPV`
from graph `(PV)_(C)gt(PV)_(D)`
BC is adiabatic expansion
so, `T_(B)gtT_(C)`
so `T_(B)gtT_(D)` and `T_(B)gtT_(A)`
maximum temperature at B or C and minimum temperature at D or A.
`T_(B)=4T_(D)`
`T_(D)=T_(A)=T_(B)`
IN process `CD:DeltaW=0,DeltaQ=DeltaU`
pressure is decreasing, volume is constant. Temperature and intenal energy will decrease.
`DeltaQ=-ve`, heat is released in CD.
In `AB,DeltaQ=nC_(P)DeltaT`
Volume is increasing and pressure is constant, temperature will increase `DeltaQ` is positive so, heat is supplied to the gas in process AB.