The maximum number of atoms which lie in the same plane in `B_(2)H_(6)` molecule is `:`

Options

A. 5
B. 6
C. 4
D. 8

Explanation

To determine the maximum number of atoms that lie in the same plane in the \( B_2H_6 \) molecule (diborane), we can analyze its structure step by step.

### Step-by-Step Solution:

1. **Understanding the Structure of \( B_2H_6 \)**:
- Diborane consists of two boron (B) atoms and six hydrogen (H) atoms.
- The molecular geometry of diborane is unique due to the presence of 3-center 2-electron bonds.

2. **Identifying the Bonds**:
- In \( B_2H_6 \), there are two types of bonds:
- **Terminal B-H bonds**: These are the bonds between the boron atoms and the terminal hydrogen atoms.
- **Bridge B-H bonds**: These involve the 3-center 2-electron bonds where two boron atoms share hydrogen atoms.

3. **Visualizing the Molecular Geometry**:
- The structure can be visualized as having two boron atoms in the center, with two hydrogen atoms bonded to each boron atom in a planar arrangement.
- The two hydrogen atoms that bridge the boron atoms are positioned above and below the plane formed by the boron and terminal hydrogen atoms.

4. **Counting Atoms in the Same Plane**:
- The four terminal hydrogen atoms and the two boron atoms lie in the same plane.
- The two bridging hydrogen atoms do not lie in this plane; they are positioned above and below it.

5. **Final Count**:
- Therefore, the total number of atoms that lie in the same plane is:
- 2 Boron atoms + 4 Terminal Hydrogen atoms = 6 atoms.

### Conclusion:
The maximum number of atoms that lie in the same plane in \( B_2H_6 \) is **6**.