`O_(2)F_(2)` is an unstable yellow change solid and `H_(2)O_(2)` is a colourless liquid, both have `O-O` bond and `O-O` bond length in `H_(2)O_(2)` and `O_(2)F_(2)` respectively is `:`

Options

A. `1.22Å, 1.48Å`
B. `1.48Å,1.22Å`
C. `1.22Å,1.22Å`
D. `1.48Å,11.48Å`

Explanation

To determine the bond lengths of the O-O bond in \( H_2O_2 \) (hydrogen peroxide) and \( O_2F_2 \) (dioxygen difluoride), we can analyze the molecular structures and the hybridization of the bonding orbitals involved.

### Step-by-Step Solution:

1. **Identify the Structures**:
- \( H_2O_2 \) has a bent structure due to the presence of two hydroxyl (–OH) groups.
- \( O_2F_2 \) also has a bent structure, but it has fluorine atoms bonded to the oxygen atoms.

2. **Consider Hybridization**:
- In \( H_2O_2 \), the oxygen atoms are involved in \( sp^3 \) hybridization because they are bonded to two hydrogen atoms and one other oxygen atom. The bond angles are approximately 109.5 degrees.
- In \( O_2F_2 \), the oxygen atoms are also \( sp^3 \) hybridized, but the presence of highly electronegative fluorine atoms affects the bond character.

3. **Analyze Bond Character**:
- The O-O bond in \( H_2O_2 \) has a significant \( s \) character due to the \( sp^3 \) hybridization. The \( O-H \) bonds also contribute to the overall bond character.
- In \( O_2F_2 \), the O-F bonds are more polar due to the high electronegativity of fluorine, which affects the electron density around the oxygen atoms.

4. **Compare Bond Lengths**:
- The bond length is inversely related to the \( s \) character of the bond. More \( s \) character means shorter bond length.
- In \( H_2O_2 \), the O-O bond length is longer because the \( s \) character is less than in \( O_2F_2 \), where the bond is influenced by the electronegative fluorine atoms.

5. **Conclusion**:
- The bond length of the O-O bond in \( H_2O_2 \) is greater than that in \( O_2F_2 \). Therefore, we can conclude:
\[ \text{Bond length in } H_2O_2 > \text{Bond length in } O_2F_2 \]

### Final Answer:
The bond length of the O-O bond in \( H_2O_2 \) is greater than that in \( O_2F_2 \).