In the, Ohm's law experiment ot find resistance of unknown resistor R, the arrangement is as shown. The resistance measured is given by `R_("measured")=(V)/(i)V=` voltage reading of voltmeter. i=current reading of ammeter. The ammeters and the voltmeter used are not ideal, and have resistance `R_(A)` and `R_(V)` respectively. For arrangement shown, the meausred resistance is

Options

A. `R+R_(V)`
B. `R+R_(A)`
C. `(RR_(v))/(R+R_(v))`
D. `(RR_(V))/(R+R_(V))+R_(A)`

Answer

B

Explanation

Potential drop `rarrV=i(R+R_(A))`
`(V)/(i)=R+R_(A)=R_("meaured")`