The figure shows the positions and velocity of two particle. If the paritcle move under the mutual attraction of each other, then the position of centre of mass at `t = 1 s` is :-

Options

A. `x = 5 m`
B. `x = 6m`
C. `x = 3m`
D. `x = 2m`

Answer

B

Explanation

`V_(CM) = ((1)(5) + (1)(-3))/(1 + 1) = 1 m//s`
Position of centre of mass at `t = 1s`
`X_(CM) = ((1)(2) + (1)(8))/(1 + 1) + (1)(1) = 5 + 1 = 6m`