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A body of mass M moves in outer space wi...

A body of mass M moves in outer space with vleocity v. It is desired to break the body into two parts so that the mass of one part is one-tenth of the total mass. After the explosion, the heavier part comes to rest whole the lighter part continues to move in the original direction of motion. The velocity of the small part will be

A

`v`

B

`((v)/(2))`

C

`((v)/(10))`

D

`10 v`

Text Solution

Verified by Experts

The correct Answer is:
D
`Mv = 0 + (M)/(10)v_(2) = 10v`
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