Four particles of masses `m, 2m, 3m, 4m` are placed at corners of a square of side 'a' as shown in fig. Find out coordinateds of centre of mass.

Answer

`((a)/(2),(7a)/(10))`

Explanation

`x_(cm) = ((m xx 0) + (2m xx a) + (3m xx a) + (4m xx 0))/(m + 2m + 3m + 4m)= (a)/(2)`
`y_(cm) = ((m xx 0) + (2m xx 0)+ (3m xx a) + (4m xx a))/(m + 2m + 3m + 4m) =(7a)/(10)`