Three identical balls eah of mass m=0.5 kg are connected with each other as shwon in figure and rest over a smooth horizontal table At moment t=0, ball B is imparted a horizontal velocity `v_(0)=9ms^(-1)` calcualte velocity of A just before it collides with ball C.

Answer

`6 ms^(-1)`

Explanation

COLM `rArr mv_(0) = 3mv_(1)`
`v_(1) = (v_(0))/(3)` …..(i) ltbr? COME
`rArr (1)/(2)mv_(0)^(2) = (1)/(2) (3m)v_(1)^(0) rArr v_(2) = (v_(0))/(sqrt3)`
Therefore velociity of `A = sqrt(v_(1)^(2) + v_(2)^(2)) = 6 m//s`