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When 4g^(3)-3g^(2)+g+k is divided by g-2...

When `4g^(3)-3g^(2)+g+k` is divided by `g-2`, the remainder is 27. What is the value of k ?

A

3

B

5

C

8

D

12

Text Solution

Verified by Experts

The correct Answer is:
B
To answer this question, start by cracking out the long division :

The question says that the remainder is 27, so whatever k is, when you subtract `-22` from it, you get 27 :
`k-(-22)=27`
`k+22=27`
`k=5`
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