If `a = 6 - b^(3)` and `b = - 2`, what is the value of a ?

Options

A. `-8`
B. `-2`
C. 2
D. 14

Explanation

To find the value of \( a \) given the equations \( a = 6 - b^3 \) and \( b = -2 \), we can follow these steps:

### Step 1: Substitute the value of \( b \) into the equation for \( a \).
We know that \( b = -2 \). We will substitute this value into the equation for \( a \):
\[ a = 6 - b^3 \]
Substituting \( b = -2 \):
\[ a = 6 - (-2)^3 \]

### Step 2: Calculate \( (-2)^3 \).
Now we need to calculate \( (-2)^3 \):
\[ (-2)^3 = -2 \times -2 \times -2 = -8 \]

### Step 3: Substitute \( (-2)^3 \) back into the equation for \( a \).
Now we will substitute \( -8 \) back into the equation:
\[ a = 6 - (-8) \]

### Step 4: Simplify the expression.
Now we simplify the expression:
\[ a = 6 + 8 \]

### Step 5: Calculate the final value of \( a \).
Now we perform the addition:
\[ a = 14 \]

Thus, the value of \( a \) is \( 14 \).