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The differential equation of a particle ...

The differential equation of a particle undergoing SHM is given
by a `a(d^(2)"x")/(dt^(2))+b"x"=0`. The particle starts from the extreme position.
The ratio of the maximum acceleration to the maximum velocity of the particle is –

A

`(b)/(a)`

B

`a/b`

C

`sqrt((a)/(b))`

D

`sqrt((b)/(a))`

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The correct Answer is:
D
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