The motion of a body is given by the equation `dv//dt=6-3v`, where v is in m//s. If the body was at rest at `t=0`
(i) the terminal speed is `2 m//s`
(ii) the magnitude of the initial acceleration is `6 m//s^(2)`
(iii) The speed varies with time as `v=2(1-e^(-3t)) m//s`
(iv) The speed is `1 m//s`, when the acceleration is half initial value

Options

A. (a) The terminal speed is 4 `m//s`
B. (b) The speed varies with the time as v(t) = 2(1 – e–5t)`m//s`
C. (c) The speed is 0.1`m//s` when the acceleration is half the initial value
D. (d) The magnitude of the initial acceleration is 6.0 `m//s^(2)`