In the system in the figure `m_(1)gtm_(2)` system is held at rest by thread `BC`. Just after the thread BC is burnt:

Options

A. acceleration of `m_(2)` will be upwards
B. magnitude of acceleration of both blocks will be equal to `((m_(1)+m_(2))/(m_(1)+m_(2)))g`
C. acceleration of `m_(1)` will be equal to zero
D. magnitude of acceleration of two blocks will be non-zro and unequal.

Answer

A, C

Explanation

When thred is burnt, tension in spring remains same `=m_(1)g`.
`m_(1)g-m_(2)gm_(2)a`
`g=((m_(1)-m_(2))/(m_(2)))` `a=` upwards
for `m_(1)` `a=0`