Two blocks of masses m and M are connected by an inextensible light string as shown in the figure. When a constant horizontal force F acts on the block of the mass M, then tension in the string: (Assume that contact between the ground and the two blocks are frictionless) (given `m=1kg,M=4kg,F=10N,theta=60^(@))`

Answer

4

Explanation

Acceleration of system `a=(F)/(M+m)`
Acceleration of mass m is also `a` then
`Tcostheta=ma`
`T=(ma)/(costheta)=(mF)/((M+m)costheta)=(1xx10xx2)/((4+1)xx1)=4N`.