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A force vecF=(3veci+4hatj)N acts on a 2 ...

A force `vecF=(3veci+4hatj)N` acts on a 2 kg movable object that moves from an initial position `vecd_(1)=(-3hatij-2hatj)m` to a final position `vecd_(f)=(5hati+4hatj)` m is 6 s. The average power (in watt) delivered by the force during the interval is equal to:

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Verified by Experts

The correct Answer is:
8
(Easy) `vecd=vecd_(f)-vecd_(i)=8hati+6hatj`
`W=vecF.vecd=24+24=48J`
`P_(av)=(W)/(t)=8`watt
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