A force of 6.4 N stretches a vertical spring by 0.1 m. The mass (in kg) that must be suspended from the spring so that it oscillates with a time period of `(pi)/(4)` second.

Answer

1

Explanation

spring constant `K=(6.4)/(0.1)=64(N)/(m)`.
Now `T=2pisqrt((m)/(k))or(pi)/(4)=2pisqrt((m)/(64))`
`becausem=1kg`