A particle is performing sinple harmonic motion of period 2 sec. if the greatest speed is `5(m)/(s)` the speed `((m)/(s))` of particle when it is `(3)/(pi)` m from equilibrium is:

Answer

4

Explanation

Angular frequency `omega=(2pi)/(2)=pis^(-1)`
`vmax=omegaA`
`4=piA`
`impliesA=(4)/(pi)m`
`v=omegasqrt(A^(2)-x^(2))`
`=pisqrt((25)/(pi^(2))-(9)/(pi^(2)))=4(m)/(s)`.