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A string fixed at both the ends of length 2m. Vibrating in its 7th overtone. Equation of the standing wave is given by `y=Asinkxcos(omegat+(pi)/(3))`. All the symbols have their usual meaning. Mass per unit length of the string is `0.5(gm)/(cm)`. Given that `A=1` cm and `omega=100pi(rad)/(sec)` Answer the following 2 questions based on information given (use `mu^(2)=10)`
Q. Starting from `t=0`, energy of vibration is completely potential at time `t`, where t is

A

`(1)/(150)sec`

B

`(1)/(60)sec`

C

`(3)/(100)sec`

D

`(11)/(300)sec`

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The correct Answer is:
A, B, D
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