An object kept on the principle axis is moving in the sme directions as that of mirror as shown in the figure. Speed of object and mirror is `10(m)/(s)` and `(40)/(13)(m)/(s)`. Radius of the curvature of the mirror is 20 cm. If the distance of object from the mirror at this instant is 5x cm, velocity of image at this instant is found to be zero. Find x.

Answer

5

Explanation

`vecV_(im)=-(v^(2))/(u^(2))vecv_(om)`
`0-(40)/(13)=-((-10)/(-10+x))^(2)(10-(40)/(13))`
`(-10)/(-10+x)=+-(2)/(3)`
`x=25,-5cm`
Object is infront of mirror
Hence `25cm`