A uniform string of length 10 m is suspended from a rigid support A short wave pulse is introduced at its lowest end it starts moving up the string the time taken to reach the support is (take `g=10m//sec^(2)`)

Answer

2

Explanation

Let mass per unit length be `mu`.
Tension at a distance `x` from lowest point is
`T=mugx`
`v=sqrt((T)/(mu))=sqrt(gx),v^(2)=gx`
`a=(vdv)/(dx)=(g)/(2),l=(1)/(2)((g)/(2))t^(2)`
`t=sqrt((4l)/(g))=sqrt((4xx10)/(10))=2sec`