In the given circuit, in steady state we may say: (capacitors are initially unchanged)

Options

A. potential drop across the capacitor `c_(1)` is `4v`
B. potential drop across `10 Omega` resistance 10 v
C. charge on `C_(1)` and `C_(2)` is `20muC`
D. ratio of charge on `C_(1)` and `C_(2)` is 1

Answer

A, D

Explanation

`C_(eq)=(10xx4)/(10+4)=(40)/(14)`
`Q=C_(eq)C=(40)/(14)xx14=40muC`
`V_(c1)=(40)/(10)=4v`
`V_(c2)=(40)/(4)=10v`.