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n' moles of an ideal gas undergoes a process `AtoB` as shown in the figure. The maximum temperature of the gas during the process will be:

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The correct Answer is:
4

Equatio of `P-V:=3P_(0)-(P_(0))/(V_(0))V`
`T=(PV)/(nR)=(3P_(0)V_(0)V-P_(0)V^(2))/(nRV_(0))`
for `T_(max)` `=(dT)/(dV)=0`
`v=(3V_(0))/(2)`
`T_(max)=(9P_(0)V_(0))/(4nR)=(9P_(0)V_(0))/(4xx3R)=(3P_(0)V_(0))/(4R)`
`lamda=4`
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