The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the order

Options

A. `S_(2)O_(6)^(2-) lt SO_(4)^(2-) lt SO_(3)^(2-)`
B. `S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`
C. `SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-)`
D. `S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-) lt SO_(3)^(2-)`

Answer

B

Explanation

`O.S. "of S in" SO_(3)^(2-) =+4`
`O.S. "of S in" SO_(4)^(2-) =+3`
`O.S. "of S in" SO_(6)^(2-) =+5`
(None of these conatains peroxide linkage).
The correct order of incresasing `O.S` is , `S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`