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Fifth group elements form hydrides to ty...

Fifth group elements form hydrides to type `AH_(3)`. The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides .
Reducing power of V-group hydrides are in order :

A

`NH_(3) gt PH_(3) gt Ash_(3) gt Sbh_(3) gt BiH_(3)`

B

`BiH_(3) gt SbH_(3) gt Ash_(3) gt PH_(3) gt NH_(3)`

C

`PH_(3) gt NH_(3) gt Ash_(3) gt SbH_(3) gt BiH_(3)`

D

`BiH_(3) gt SbH_(3) gt Ash_(3) gt NH_(3) gt PH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
A-H bond energy derceases with increase in size of A. Hence Bi-H bond radily breaks to make it the best reducer and the reducing power decreases with decrease of size of A.
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Fifth group elements form hydrides to type AH_(3) . The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides . The H-M-H bond angle of V group hydrides decrease from 107^(circ) to 90^(circ) for NH_(3) to SbH_(3) , this is due to:

Fifth group elements form hydrides to type AH_(3) . The hydrides have a lone pair of electrons. The hydries are reducing in nature and the reducing power is related to the stability of A-H bonds. The hydrides are covalent and low boiling. Their boiling points depends on their ability to from hydrogen bond and their molecular size which decide the intermolcular forces in the hydrides . The boiling points of the hydrides of V-group elements are in the order :

Which of the following is the correct order of reducing power of hydrides ?