Home
Class 11
PHYSICS
A thin circular ring of area A is held p...

A thin circular ring of area A is held perpendicular to a uniform magnetic field of induction B. A small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of the circuit is R. When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is

A

`(BR)/(A)`

B

`(AB)/(R )`

C

ABR

D

`(B^(2)A)/(R^(2))`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CHARGE AND FIELDS

    DISHA|Exercise Physics|42 Videos

  • ELECTROMAGNETIC WAVES

    DISHA|Exercise PHYSICS|43 Videos

Similar Questions

Explore conceptually related problems

A thin circular ring of area A is perpendicular to uniform magnetic field of induction B . A small cut is made in the ring and a galavanometer is connected across the ends such that the total resistance of circuit is R . When the ring is suddenly sqeezed to zero area, the charge flowing through galvanometer is:

Metal ring of radius R is placed perpendicular to uniform magnetic field B. Magnetic field starts changing at a rate alpha

A coil of 30 turns of wire each of 10 cm^(2) area is placed with its plance perpendicular to a magnetic field of 0.1 T . When the coil is suddenly withdraw from the field, a galvanometer connected in series with the coil indicated that a 10 mu C charge passes around the circuit. The combined resistance of the coil and galvanometer is

A thin semicircular conducting ring of radius R is falling with its plane verticle in a horizontal magnetic inducting B . At the position MNQ , the speed of the ring is V and the potential difference developed across the ring is

A metal rod of mass m can rotate about a horizontal axis O , sliding along a circular conductor of radius a (fig). The arrangment is located in a unifrom magnetic field of induction B directed perpendicular to the ring plane. The axis and the ring are connected to an emf source to form a circuit of resistance R . Neglecting the friction, circuit induction and ring resistance, find the law according to which the source and must very to make the rod rotate with a constant angular velocity omega .

A small coil of N turns has its plane perpendicular to a uniform magnetic field as shown in Fig. 30-5. The coil is connected to a Ballistic galvanometer, a device designed to measure the total charge passing through it. Find the charge passing through the coil if the coil is rotated through 180° about its diameter.

A semi circular conducting ring acb of radius R moves with constant speed v in a plane perpendicular to uniform magnetic field B as shown in figure. Identify the correct statement.

Winding wire with insulated coating is used to make a circular ring whose area is A. This ring is kept perpendicular to a uniform magnetic field B. If ring is suddenly squeezed to zero area then how much charge will flow through the wire? R is resistance of winding wire.

A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction B. At the position MNQ shown in the fig, the speed of the ring is V. The potential difference developed across the semicircular ring is

A small cylindrical magnet M (Fig) is placed in the centre of a thin coil of radius a consisting of N turns. The coil in connected to a ballistic galvanometer. The active resistance of the whole circuit is equal to R . Find the magnetic moment of the magnet if its removel from the coil results in a charge q flowing through the galvanometer.

DISHA-ELECTROMAGNETIC INDUCTION-PHYSICS
  1. Choke coil works on the principle of

    Text Solution

    |

  2. A coil having n turns and resistance R Omega is connected with a galva...

    Text Solution

    |

  3. A thin circular ring of area A is held perpendicular to a uniform magn...

    Text Solution

    |

  4. A boat is moving due east in a region where the earth's magnetic field...

    Text Solution

    |

  5. A coil of area 10cm^2 and 10 turns is in magnetic field directed perpe...

    Text Solution

    |

  6. A horizontal straight wire 20 m long extending from east to west falli...

    Text Solution

    |

  7. The self inductance of a long solenoid cannot be increased by

    Text Solution

    |

  8. A metallic rod of length 'l' is tied to a string of length 2l and made...

    Text Solution

    |

  9. Lenz's law gives:

    Text Solution

    |

  10. A metal ring is held horizontally and bar magnet is dropped through th...

    Text Solution

    |

  11. The pointer of a dead-beat galvanometer gives a steady deflection beca...

    Text Solution

    |

  12. A metal rod of length l cuts across a uniform magnetic field B with a ...

    Text Solution

    |

  13. In an A.C. generator, when the plane of the armature is perpendicular ...

    Text Solution

    |

  14. A copper disc of radius 0.1 m rotates about its centre with 10 revolut...

    Text Solution

    |

  15. The mutual inductance of a pair of coils, each of N turns, is M henry....

    Text Solution

    |

  16. Consider the situation shown in . if the switch is closed and after so...

    Text Solution

    |

  17. A magnet is moved towards a coil (i) quickly (ii) slowly, then the ind...

    Text Solution

    |

  18. A circular wire of radius r rotates about its own axis with angular sp...

    Text Solution

    |

  19. A conducting ring of radius l m kept in a uniform magnetic field B of ...

    Text Solution

    |

  20. A magnetic field of 2xx10^(-2)T acts at right angles to a coil of area...

    Text Solution

    |