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At 300 K and 1 atm, 15 mL of a gaseous h...

At `300 K` and `1 atm, 15 mL` of a gaseous hydrocarbon requires `375 mL` air containing `20% O_(2)` by volume for complete combustion. After combustion, the gases occupy `330 mL`. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is

A

`C_(3)H_(8)`

B

`C_(4)H_(8)`

C

`C_(4)H_(10)`

D

`C_(3)H_(6)`

Text Solution

AI Generated Solution

To determine the formula of the hydrocarbon, we will follow these steps: ### Step 1: Determine the volume of O₂ used in the combustion Given that the air contains 20% O₂ by volume, we can calculate the volume of O₂ in the 375 mL of air. \[ \text{Volume of O}_2 = \frac{20}{100} \times 375 \, \text{mL} = 75 \, \text{mL} \] ...
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