The molecular formula of a commercial resin used for exchanging ions in water softening is `C_(8)H_(7)SO_(3)Na(mol. Wt. 206)` . What would be the maximum uptake of `Ca^(2+)` ions by the resin when expressed in mole per gram resin?
A
`(1)/(103)`
B
`(1)/(206)`
C
`(2)/(309)`
D
`(1)/(412)`
Text Solution
Verified by Experts
The correct Answer is:
D
We know the molecular weight of `C_(8)H_(7)SO_(3)Na` `=12 xx 8 + 1xx7 + 32+16 xx 3 + 23 = 206` we have to find, mole per gram of resin. `:. 1g` of `C_(8)H_(7)SP_(3)Na` has number of mole `= ("weight of given resin")/("Molecular, weight of resin") = (1)/(206)mol` Now, reaction looks like `2C_(8)H_(7)SO_(3)Na+Ca^(2+) rarr (C_(8)H_(7)SO_(3))_(2)Ca+2Na` `because` 2 moles of `C_(8)H_(7)SO_(3)Na` will combine with `(1)/(2) mol Ca^(2+)` `:. (1)/(2)` mole of `C_(8)H_(7)SO_(3)Na` will combine with `(1)/(2) xx (1)/(206) mol Ca^(2+) = (1)/(412)mol Ca^(2+)`
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