`3g` of actived chacoal was added to 50mL of acetic acid solution `(0.06N)` in a flask. After an hour it was filterred and the strength of the filtrate was found to be `0.042N` . The amount of acetic adsorbed (per gram of charcoal) is:
A
`18 mg`
B
`36 mg`
C
`42 mg`
D
`54 mg`
Text Solution
Verified by Experts
The correct Answer is:
D
Given, initial strength of acetic acid `= 0.06 N` Final strength `= 0.042 N`, Volume `= 50 mL` `:.` Initial millimoles of `CH_(3)COOH = 0.06 xx 50 = 3` Final millimoles of `CH_(3)COOH` adsorbed `= 3-2.1 = 0.9 mmol = 0.9 xx 60 mg = 54 mg`
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