Given that the abundacne of isotopes `.^(54)Fe`, `.^(56)Fe`, and `.^(57)Fe` is 5%, 90% and 5% respectively. The atomic mass of `Fe` is
A
`55.85`
B
`55.95`
C
`55.75`
D
`56.05`
Text Solution
Verified by Experts
The correct Answer is:
B
From the given relative abundance, the average weight of Fe can be calculated as `A = (54 xx 5 + 56 xx 90 + 57 xx 5)/(100) = 55.95`
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