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A mixture x containing 0.02 mol of [Co(N...

A mixture `x` containing 0.02 mol of `[Co(NH_(3))_(5) SO_(4)]Br` and 0.02 mol of `[Co(NH_(3))_(5)Br]SO_(4)` was prepared in `2 L` of solution.
`1 L` of mixture `X + ` excess `AgNO_(3) rarr Y`
`1 L` of mixture `X +` excess `BaCl_(2) rarr Z`
The number of moles of `Y` and `Z` are

A

`0.01, 0.01`

B

`0.02, 0.01`

C

`0.01, 0.02`

D

`0.02, 0.02`

Text Solution

Verified by Experts

The correct Answer is:
A
`1.0L` of mixture X contain `0.01` mole of each `[(Co(NH_(3))_(5)SO_(4))]Br` and `[Co(NH_(3))_(5)Br)]SO_(4)`. Also, with `AgNO_(3)`, only `[(Co(NH_(3))_(5)SO_(4))]Br` reacts to give `AgBr` precipitate as
`underset(1.0 mol)([Co(NH_(3))_(5)SO_(4)]Br) + underset("Excess")(AgNO_(3)) rarr [Co(NH_(3))_(5)SO_(4)]NO_(3)+underset(1.0 mol)(AgBr)`
With `BaCl_(2)`, only `[Co(NH_(3))_(5)Br)]SO_(4)` reacts giving `BaSO_(4)` precipitate as
`underset(1.0 mol)([Co(NH_(3))_(5)Br]SO_(4)) + underset("Excess")(BaCl_(2))rarr [Co(NH_(3))_(5)Br]Cl_(2)+underset(1 mol)(BaSO_(4))`
Hence, moles of Y and Z are `0.01` each.
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