Number of molecules present in `36 g` of water `= (36)/(18) xx N_(A) = 2N_(A)` Number of molecules present in `28g` of `CO = (28)/(28) xx N_(A) = N_(A)` Number of molecules present in `46 g` of `C_(2)H_(5)OH = (46)/(46) xx N_(A) = N_(A)` Number of molecules present in `54 g` of `N_(2)O_(5) = (54)/(108) xx N_(A) = 0.5 N_(A)` Here, `N_(A)` is Avogadro's number. Hence, `36 g` of water contain the largest `(2N_(A))` number of molecules.
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