A gases mixture contains oxygen and nitrogen in the ratio `1 : 4` by weight. Therefore, the ratio of the number of molecules is:
A
`1:4`
B
`1:8`
C
`7:32`
D
`3:16`
Text Solution
Verified by Experts
The correct Answer is:
C
`("Weight of a compound in gram (w)")/("Molar mass (M)") = "Number of moles(n)"` `= ("Number of molecules (N)")/("Avogadro number" (N_(A)))` `rArr (w(O_(2)))/(32) = (N(O_(2)))/(N_(A))` ....(i) And `(w(N_(2)))/(28) = (N(N_(2)))/(N_(A))` .... (ii) Dividing Eq. (i) by Eq. (ii) gives `(N(O_(2)))/(N(N_(2))) = (w(O_(2)))/(w(N_(2))) xx (28)/(32) = (1)/(4) xx (28)/(32) = (7)/(32)`
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